#include <stdio.h> 
#include <stdlib.h> 
#include <string.h> 

int main() 
{ 
 int size = 1024; 
 char* buff = (char*)malloc(size); 

 // read lines 
 while(NULL != gets(buff)){ 
 printf("Read line with len: %d\n", strlen(buff)); 
 printf("%s", buff); 
 } 

 // free buff 
 free(buff); 
} 

#include <stdio.h> 
#include <stdlib.h> 

int my_getline(char* line, int max_size) 
{ 
 int c; 
 int len = 0; 
 while( (c = getchar()) != EOF && len < max_size ){ 
 line[len++] = c; 
 if('\n' == c) 
  break; 
 } 


 line[len] = '\0'; 
 return len; 
} 

int main() 
{ 
 int max_size = 1024; 
 char* buff = (char*)malloc( sizeof(char) * max_size ); 

 //getline 
 int len; 
 while(0 != (len = my_getline(buff, max_size))){ 
 printf("Read line with len: %d\n", len); 
 printf("%s", buff); 
 } 

 free(buff); 
} 

cin.get()和cin.getline()
#include<iostream>

using namespace std;

int main()
{

 cout << "----------getline忽略'\\n-----------------" << endl;
 char str0[30], str1[30];
 cin.getline(str0, 30);
 cin.getline(str1, 30);
 cout << "str0:" << str0 << endl;
 cout << "str1:" << str1 << endl;

 cout << "---------利用get()消除get()遺留下來(lái)的'\\n'-------" << endl;
 char str2[30], str3[30];
 cin.get(str2, 30).get(); // 注意這里！
 cin.get(str3, 30).get();
 cout << "str1: " << str2 << endl;
 cout << "str2: " << str3 << endl;

 cout << "--------沒消除get()遺留下來(lái)的'\\n'就被下一個(gè)get()讀取了，所以str5輸出為空-----" << endl;
 char str4[30], str5[30];
 cin.get(str4, 30); // 注意這里！
 cin.get(str5, 30);
 cout << "str4: " << str4 << endl;
 cout << "str5: " << str5 << endl;
 return 0;

}