C語言數(shù)據(jù)結(jié)構(gòu)之迷宮問題
本文實例為大家分享了數(shù)據(jù)結(jié)構(gòu)c語言版迷宮問題棧實現(xiàn)的具體代碼,供大家參考,具體內(nèi)容如下
程序主要參考自嚴(yán)蔚敏老師的數(shù)據(jù)結(jié)構(gòu)c語言版,在書中程序的大體框架下進行了完善。關(guān)于迷宮問題的思路可查閱原書。
#include<iostream>
using namespace std;
#define MAXSIZE 10
typedef int Status;
typedef struct{
int x;
int y;
}Postype;
typedef struct{
int ord;
Postype seat;
int dir;
}SElemType;//棧的元素類型
typedef struct{
//SElemType data[MAXSIZE];
SElemType* top;
SElemType* base;
}Stack;//棧的結(jié)構(gòu)類型
typedef struct{
char arr[MAXSIZE][MAXSIZE];
}MAZETYPE;//迷宮結(jié)構(gòu)體
MAZETYPE maze;
void InitMaze()
{
maze.arr[0][0] = maze.arr[0][1] = maze.arr[0][2] = maze.arr[0][3] = maze.arr[0][4] = maze.arr[0][5] = maze.arr[0][6] = maze.arr[0][7] = maze.arr[0][8] = maze.arr[0][9] = '1';
maze.arr[1][0] = maze.arr[1][3] = maze.arr[1][7] = maze.arr[1][9] = '1';
maze.arr[1][1] = maze.arr[1][2] = maze.arr[1][4] = maze.arr[1][5] = maze.arr[1][6] = maze.arr[1][8] = '0';
maze.arr[2][0] = maze.arr[2][3] = maze.arr[2][7] = maze.arr[2][9] = '1';
maze.arr[2][1] = maze.arr[2][2] = maze.arr[2][4] = maze.arr[2][5] = maze.arr[2][6] = maze.arr[2][8] = '0';
maze.arr[3][0] = maze.arr[3][5] = maze.arr[3][6] = maze.arr[3][9] = '1';
maze.arr[3][1] = maze.arr[3][2] = maze.arr[3][3] = maze.arr[3][4] = maze.arr[3][7] = maze.arr[3][8] = '0';
maze.arr[4][0] = maze.arr[4][2] = maze.arr[4][3] = maze.arr[4][4] = maze.arr[4][9] = '1';
maze.arr[4][1] = maze.arr[4][5] = maze.arr[4][6] = maze.arr[4][7] = maze.arr[4][8] = '0';
maze.arr[5][0] = maze.arr[5][4] = maze.arr[5][9] = '1';
maze.arr[5][1] = maze.arr[5][2] = maze.arr[5][3] = maze.arr[5][5] = maze.arr[5][6] = maze.arr[5][7] = maze.arr[5][8] = '0';
maze.arr[6][0] = maze.arr[6][2] = maze.arr[6][6] = maze.arr[6][9] = '1';
maze.arr[6][1] = maze.arr[6][3] = maze.arr[6][4] = maze.arr[6][5] = maze.arr[6][7] = maze.arr[6][8] = '0';
maze.arr[7][0] = maze.arr[7][2] = maze.arr[7][3] = maze.arr[7][4] = maze.arr[7][6] = maze.arr[7][9] = '1';
maze.arr[7][1] = maze.arr[7][5] = maze.arr[7][7] = maze.arr[7][8] = '0';
maze.arr[8][0] = maze.arr[8][1] = maze.arr[8][9] = '0';
maze.arr[8][2] = maze.arr[8][3] = maze.arr[8][4] = maze.arr[8][5] = maze.arr[8][6] = maze.arr[8][7] = maze.arr[8][8] = '0';
maze.arr[9][0] = maze.arr[9][1] = maze.arr[9][2] = maze.arr[9][3] = maze.arr[9][4] = maze.arr[9][5] = maze.arr[9][6] = maze.arr[9][7] = maze.arr[9][8] = maze.arr[9][9] = '1';
}
Status initStack(Stack &s)
{
s.base = (SElemType*)malloc(MAXSIZE*sizeof(SElemType));
if (!s.base) return 0;
s.top = s.base;
return 1;
}
void Push(Stack &s, SElemType e)
{
*s.top++ = e;
}
void Pop(Stack &s, SElemType &e)
{
e = *--s.top;
}
Status StackEmpty(Stack &s)
{
if (s.top == s.base) return 1;
else return 0;
}
Status Pass(Postype curpos)
{
if (maze.arr[curpos.x][curpos.y] == '0')
return 1;
else return 0;
}
void Foot(Postype curpos)
{
maze.arr[curpos.x][curpos.y] = '*';
}
void MarkPrint(Postype curpos)
{
maze.arr[curpos.x][curpos.y] = '!';
}
Status StructCmp(Postype a, Postype b)
{
if (a.x = b.x&&a.y == b.y) return 1;
else return 0;
}
//下一個位置
Postype NextPos(Postype CurPos, int Dir)
{
Postype ReturnPos;
switch (Dir)
{
case 1:
ReturnPos.x = CurPos.x;
ReturnPos.y = CurPos.y + 1;
break;
case 2:
ReturnPos.x = CurPos.x + 1;
ReturnPos.y = CurPos.y;
break;
case 3:
ReturnPos.x = CurPos.x;
ReturnPos.y = CurPos.y - 1;
break;
case 4:
ReturnPos.x = CurPos.x - 1;
ReturnPos.y = CurPos.y;
break;
}
return ReturnPos;
}
Status MazePath(Postype start, Postype end)
{
Stack s;
SElemType e;
initStack(s);
Postype curpos = start;
int curstep = 1;
do{
if (Pass(curpos))
{
Foot(curpos);
e = { curstep, curpos, 1 };
Push(s, e);
if (StructCmp(curpos, end)) return 1;
curpos = NextPos(curpos, 1);
curstep++;
}
else
{
if (!StackEmpty(s))
{
Pop(s, e);
while (e.dir ==4 &&!StackEmpty(s))
{
MarkPrint(e.seat); Pop(s, e);
}
if (e.dir < 4 && !StackEmpty(s))
{
e.dir++;
Push(s, e);
curpos = NextPos(e.seat, e.dir);
}
}
}
} while (!StackEmpty(s));
return 0;
}
int main()
{
InitMaze();
Postype s, e;
s.x = s.y = 1;
e.x = e.y = 8;
if (MazePath(s, e))
printf("迷宮成功解密!\n");
else
printf("解密失敗\n");
for (int i = 0; i < 10; i++)
{
for (int j = 0; j < 10; j++)
{
printf("%c ", maze.arr[i][j]);
}
printf("\n");
}
cout << "-=================================" << endl;
for (int i = 0; i < 10; i++)
{
for (int j = 0; j < 10; j++)
{
if (maze.arr[i][j] == '*' || maze.arr[i][j] == '!')
printf("%c ", maze.arr[i][j]);
else cout << " ";
}
printf("\n");
}
}
以上就是本文的全部內(nèi)容,希望對大家的學(xué)習(xí)有所幫助,也希望大家多多支持我們。
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