#include <iostream>
#include <string>
#include <cmath>
using namespace std;

//將任意字符轉(zhuǎn)換為十進(jìn)制，其中a-z代表10-35，A-Z代表36-61，用對應(yīng)的ASCII碼調(diào)整就好
long long convertToDec(char c)
{
 long long decNum;
 if(c>='a' && c<='z')
  decNum=c-87;
 else if(c>='A' && c<='Z')
  decNum=c-29;
 else if(c>='0' && c<='9')
  decNum=c-48;

 return decNum;
}

//將十進(jìn)制轉(zhuǎn)換為這些字符
char convertToDec(long long c)
{
 long long objchar;
 if(c>=10 && c<=35)
  objchar=c+87;
 else if(c>=36 && c<=61)
  objchar=c+29;
 else if(c>=0 && c<=9)
  objchar=c+48;

 return objchar;
}

int main()
{
 int src;
 int obj;
 string num;

 while(cin>>src>>obj>>num)
  {

   bool IsNegative=false;
   if(num[0]=='-')
    {
     num.erase(0);
     IsNegative=true;
    }

   long long decNum=0;//十進(jìn)制數(shù)（中間數(shù)）
   for(long long i=0;i<num.size();++i)
    decNum+=convertToDec(num[i])*pow(src,num.size()-1-i);

   string strTmp;
   long long tmp;
   while(decNum>0)
    {
     tmp=decNum % obj;
     strTmp=convertToDec(tmp)+strTmp;
     decNum/=obj;
    }

   if(IsNegative)
    strTmp='-'+strTmp;
   cout<<strTmp<<endl;
  }

 return 0;
}